Pour 1 ml of sulfuric acid solution into a test tube and add the same amount of barium chloride solution

Pour 1 ml of sulfuric acid solution into a test tube and add the same amount of barium chloride solution. Write their equations in molecular, full and abbreviated ionic form.

Molecular form of the equation:

BaCl2 + H2SO4 → BaSO4 ↓ + 2HCl (as a result of the interaction of solutions of barium chloride and sulfuric acid, a white precipitate is formed).

Full ionic form of the equation:

Ba2 + + 2Cl- + 2H + + SO42- → BaSO4 ↓ + 2H + + 2Cl-.

Abbreviated ionic form of the equation:

Ba2 + + SO42- → BaSO4 ↓.



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