Power plants generate alternating current with a frequency of 50-60 Hz. Calculate the periods of oscillation of these currents.

v1 = 50 Hz.
v2 = 60 Hz.
T1 -?
T2 -?
The oscillation period T is the time of one complete oscillation. Since the frequency v is the number of oscillations per unit of time, then T = 1 / v.
T1 = 1 / v1.
T2 = 1 / v2.
T1 = 1/50 Hz = 0.02 s.
T2 = 1/60 Hz = 0.016 s.
Answer: the period of alternating current oscillations is T1 = 0.02 s, T2 = 0.016 s.

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