Prepare 500 grams of 22% sulfurous acid solution.

univerkov | September 25, 2021 | education

Given:
m solution (H2SO3) = 500 g
ω (H2SO3) = 22%

Find:
m (H2SO3) -?
m (H2O) -?

Solution:
1) m (H2SO3) = ω (H2SO3) * m solution (H2SO3) / 100% = 22% * 500/100% = 110 g;
2) m (H2O) = m solution (H2SO3) – m (H2SO3) = 500 – 110 = 390 g.

Answer: The mass of H2SO3 is 110 g; H2O – 390 g.

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