Print the molecular formula of a hydrocarbon, the mass fraction of hydrogen
Print the molecular formula of a hydrocarbon, the mass fraction of hydrogen in which is 20%, and the density of the hydrocarbon in air is 1.035.
Given:
w% (H) = 20%
D (= 1.035
To find:
Formula -?
Decision:
1) Let us find the molecular weight of the hydrocarbon by its density in air:
D (air) = Mr (HC): Mr (air), – since air does not have a certain molecular weight, it is conventionally taken as 29.
Mr (HC) = D (air) * 29 = 1.035 * 29 = 30
2) Knowing the mass fraction of hydrogen, we find its molecular weight in the substance and the number of atoms:
30 – 100%
x – 20%,
then x = 20% * 30: 100% = 6.
N (H) = 6: Mr (H) = 6: 1 = 6 atoms.
3) Then the molecular weight of carbon accounts for 30 – 6 = 24.
N (C) = 24: Mr (C) = 24: 12 = 2 atoms.
We got a substance with the formula C2H6 – ethane.
Answer: C2H6 is ethane.