Prove that the diagonals of a rhombus divide it into four equal triangles.

In a rhombus, all 4 sides are equal to “a”, the diagonals intersect at an angle <90 °, and each of the two diagonals d1 and d2 are divided into two equal parts. It turns out 4 triangles, each consists of sides “a”; d1 / 2; d2 / 2. And this is equality on three sides, the triangles are equal.



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