Prove that the diagonals of the parallelogram are halved by the intersection point
| February 6, 2021 | education
Let AВСD be a parallelogram, in which, by definition, AB = СD, BC = AD, AC and ВD are diagonals, point O is the point of intersection of the diagonals.
Consider triangles ABO and CDO. These triangles are equal, since AB = СD, <ABO = <SСDO, <ВAO = <DСO. And in equal triangles opposite equal angles there are equal sides. Hence, AO = OC, BO = OD. This means that the diagonals AC and ВD are halved by point O.
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