Prove the equality of the triangles along the side, the adjacent angle and the bisector of this angle.

Given:
triangle ABC,
triangle A1B1C,
angle A = angle A1,
bisectors AD = A1D1,
AC = A1C1.
Prove that triangle ABC = A1B1C1.
Evidence:
1) Into triangle АDC = triangle A1D1C1 according to the first sign of equality of triangles, as angle DAC = angle D1A1C1 (angle DAC is half of angle BAC, angle DAC = angle BAC: 2 = angle B1A1C1: 2 = angle D1A1C1). AD = A1D1, AC = A1C1 (by condition: AD = A1D1 – equal bisectors, AC = A1C1 – equal adjacent sides) Then angle С = angle С1;
2) triangle ABC = triangle A1B1C1 according to the first sign of equality of triangles AC = A1C1, angle A = angle A1 (by condition) angle C = angle C1.
Q.E.D.