Prove the equality of triangles along the side of the bisector and the height attached to this side.
| November 19, 2020 | education
In ΔABD and ΔA1B1D1:
AB = A1B1, AD = A1D1, BD = B1D1, thus, ΔABD = ΔA1B1D1 according to the 3rd sign of triangle equality. Whence ΔABD = ΔA1BD1.
В ΔАВС and ΔА1В1С1: АВ = А1В1
ВС = В1С1 (according to the problem statement)
∠ABD = ∠A1B1D1, thus, ΔАВС = ΔА1В1С1 according to the 1st sign of equality of triangles.
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