Raising a load of 100 N uniformly using a movable block, the worker applies a force of 70 N. What is the efficiency of this block?

Efficiency = Ap * Az * 100% = Fp / Fz * 100%
For the movable block, the gain in strength is 2 times in, therefore Fz = 2F
Efficiency = 100n / 2 * 70n * 100% = 71%
Hence the answer: efficiency is 71%



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