Rectangle length 9cm width 4cm Find the perimeter of the square, the area of which is equal to the area of the rectangle.

Let’s find the area S of the given rectangle.
According to the condition of the problem, the length of this rectangle is 9 cm, and the width of this rectangle is 4 cm.
Since the area of ​​any rectangle is equal to the product of the length and width of this rectangle, the area of ​​this rectangle is:
S = 9 * 4 = 36 cm².
Find the side of a square whose area is equal to the area of ​​this rectangle.
Let us denote it by x.
Since the area of ​​any square is equal to the side of the square to the second power, we can write the following equation:
x² = 36.
We solve the resulting equation:
x² = 6².
x1 = -6;
x2 = 6.
Since the length of the side of the square is positive, the value x = -6 is not suitable.
We find the perimeter p of this square:
p = 6 + 6 + 6 + 6 = 4 * 6 = 24 cm.
Answer: the perimeter of the square is 24 cm.