Rectangle width 4 m length 12 cm, find the area of a rectangle with the same perimeter.
The width of the rectangle (apr.) – 4 cm;
The length of the rectangle (bpr.) – 12 cm;
Square area Sq. -? cm ^ 2.
Perimeter of the rectangle (Ppr.) = (Pkv.)
The perimeter of the rectangle is found according to the formula:
Ppr. = (apr. + bpr.) * 2.
We substitute the known values into this formula and find the value of the perimeter of the rectangle:
Ppr. = (4 + 12) * 2 = 16 * 2 = 32 (cm).
The perimeter of the square is found by the formula: Pkv. = 4 * aq.
By condition, the perimeter of the rectangle is equal to the perimeter of the square, i.e. 4 * aq. = 32, therefore, the side of the square is equal to aq. = 32: 4 = 8 cm.
The area of the square is calculated by the formula:
Sq. = (aq.) ^ 2 = 8 ^ 2 = 64 (cm ^ 2).
Answer: the area of the square is 64 cm ^ 2.