Resistors with resistance R1 = 300 Ohm and R2 = 600 Ohm are connected in parallel.
Resistors with resistance R1 = 300 Ohm and R2 = 600 Ohm are connected in parallel. Find the current in the first resistor if the current in the second resistor is 0.4 A.
R1 = 300 ohms.
R2 = 600 ohms.
I2 = 0.4 A.
I1 -?
For parallel connection of conductors, the following ratios are valid:
I = I1 + I2, U = U1 = U2, R = R 1 * R2 / (R 1 + R2).
Where I1, I2 are the current in the first and second resistor, U1, U2 are the voltage across the first and second resistor, R 1, R2 m are the resistance of the first and second resistor, I, U, R are the current strength, voltage, resistance of the entire section chains
According to Ohm’s law for a section of the circuit, we express the voltage across the second resistor U2.
I2 = U2 / R2.
U2 = I2 * R2.
Let’s write Ohm’s law for the first resistor: I1 = U1 / R1. Since U = U1 = U2, then
I1 = U2 / R1 = I2 * R2 / R1.
I1 = 0.4 A * 600 Ohm / 300 Ohm = 0.8 A.
Answer: the current in the first resistor is I1 = 0.8 A.