Right-angled triangles B Δ ABC angle A = angle B = 45 °, AB = 19 cm. Find the projection of the segment

Right-angled triangles B Δ ABC angle A = angle B = 45 °, AB = 19 cm. Find the projection of the segment AC on line AB.

The projection of a segment onto a straight line is equal to the distance from the point of intersection of a segment with a straight line to the point of intersection of a perpendicular dropped from the second end of the segment onto a straight line with this straight line.

AC projection on AB = AН, CH – perpendicular from point C to AB;

Triangle ABC is isosceles, since <A = <B = 45 °;

CH in an isosceles triangle is the median, which means:

AH = 1/2 AB = 1/2 * 19 = 9.5.



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