Sawing logs with an electric saw performed work equal to 90 kJ in 1.5 minutes. What energy was expended on this?

Sawing logs with an electric saw performed work equal to 90 kJ in 1.5 minutes. What energy was expended on this? disregarding its losses, find the current power in the electric saw motor

These tasks: A (work performed by the electric saw) = 90 kJ (90 * 10 ^ 3 J); t (duration of the electric saw) = 1.5 minutes = 90 s.
1) To carry out the work on sawing the logs, the energy of the electric current was used: W = U * I * t = P * t = A = 90 kJ.
2) The power of the current in the motor of the used electric saw: P = A / t = 90 * 10 ^ 3/90 = 1 * 10 ^ 3 W (1 kW).
Answer: The current power in the motor of the used electric saw is 1 kW; energy of 90 kJ was expended to perform the work.