Schoolchildren play ball, throwing it to each other. What is the greatest height the ball will reach during

Schoolchildren play ball, throwing it to each other. What is the greatest height the ball will reach during the game if it flies from one player to another t = 2s? The height is measured from the point of throw.

Given:

t = 2 seconds – the flight time of the sword from one student to another;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the maximum flying height of the sword H (meter).

Since it is not specified in the problem statement, air resistance is not taken into account.

The trajectory of the sword’s flight is as follows: from one student it rises to a height H, and why does it descend to another student. Since the time of raising the sword is equal to the time of its fall, the flight time to the maximum height H is equal to t1 = t / 2.

Let the schoolchildren throw swords at a certain speed, the vertical component of which is V0. Then at maximum altitude this speed will be zero, or

V0 – g * t1 = 0

V0 = g * t = 10 * 1 = 10 m / s.

H = V0 * t – g * t ^ 2/2 = 10 * 1 – 10 * 1 ^ 2/2 = 10 – 5 = 5 meters.

Answer: The ball will reach the maximum height of 5 meters.



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