Scuba divers reach a depth of 40 meters. What is the pressure of the sea water at this depth?

To find the pressure value for seawater scuba divers, we apply the formula: P = ρmw * g * h.

Variables and constants: ρmw is the density of seawater (ρmw = 1010 … 1050 kg / m3; we take ρmw = 1030 kg / m3); g — acceleration of gravity (g = 9.81 m / s2); h – indicated depth (h = 40 m).

Calculation: P = ρmv * g * h = 1030 * 9.81 * 40 = 404172 Pa ≈ 404.2 kPa.

Answer: At a depth of 40 m, scuba divers experience a pressure of 404.2 kPa from the seawater.