# Segment BF – isosceles triangle meridian AB (AB = BC). Point O lies on the side BC, the segment

March 29, 2021 | education

| **Segment BF – isosceles triangle meridian AB (AB = BC). Point O lies on the side BC, the segment OP is the height of the triangle FOC. Are the lines BF and OP parallel?**

By the condition of the problem, the segment BF is the median, and in an isosceles triangle there is also a bisector and a height. We are interested in the height, the BFC angle is 90 °.

In the FOC triangle, the segment OP is the conditional height, the OPC angle is 90 °.

Consider straight lines BF, OP and AC intersecting to them.

∠BFC = ∠OРС = 90 °.

These two angles are corresponding with straight lines BF, OP and secant AC and they are equal. We conclude that lines BF and OP are parallel.