Segment BK -median of isosceles triangle ABC; AB = CB, BK = 4cm. The base of the triangle is 2cm
Segment BK -median of isosceles triangle ABC; AB = CB, BK = 4cm. The base of the triangle is 2cm more than the median BK. The side is 1cm less than the base. Find the perimeters of triangles ABC and KBC.
The solution of the problem:
1. Let’s find what the base of the isosceles triangle ABC is equal to.
4 + 2 = 6 centimeters.
2. Let’s find what the lateral side of the isosceles triangle ABC is equal to.
6-1 = 5 centimeters.
The perimeter of a triangle is equal to the sum of all sides.
3. Find what the perimeter of an isosceles triangle ABC is equal to.
5 + 5 + 6 = 16 centimeters.
To find the perimeter of the PIC triangle, you need to know what the side of the KS of this triangle is equal to.
4. Find the side of the COP.
6/2 = 3 centimeters.
5. Find the perimeter of the PBC triangle.
5 + 4 + 3 = 12 centimeters.
Answer: the perimeter of the ABC triangle = 16 cm. The KBC triangle = 12 cm.