Segment CH – the height of the right-angled triangle ABC to the hypotenuse AB, BC = 6, BH = 3√3. Find cos A.

cos A = cos (<HCB) = CH / CB = 3/5 = 0.5; <A = <HCB = 60 °.
<A = <HCB, as angles with mutually perpendicular sides.



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