Segments AB and CD are parallel and equal. Prove that triangle AOB = triangle DOC, where O is the intersection

Segments AB and CD are parallel and equal. Prove that triangle AOB = triangle DOC, where O is the intersection point of the segments AD and BC.

Triangle AOB = triangle DOC according to 2 signs: AB = CD (by condition), angle BAD = angle CDA (cross-lying angles at secant BP and parallel segments AB and CD), angle ABC = angle DCB (cross-lying angles at secant BC and parallel segments AB and CD)

 



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