Segments AB and CD meet at their midpoint at point M. Prove that AC is parallel to DB.
| April 27, 2021 | education
Triangles AMC and BMD are equal, since they have 2 sides and the angle between them:
AM = BM, CM = DM, angle AMC = angle BMD.
Therefore angle ACM = angle BDM.
These angles are crossed for lines containing segments AC and BC and a secant containing segment CD.
The angles of parallel lines lying across the line are equal, so the line segments AC and BD are parallel.
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