Segments AB and CM intersect at point O so that AC || BM. Find the length of the segment CM, if AC = 15 cm, BM = 3 cm, CO = 10 cm.

Let us prove that triangles AOC and BOM are similar.
∠AOC = ∠BOM as vertical angles at the intersection of straight lines AB and CM
∠АСО = ∠ОМВ as criss-crossing angles at the intersection of parallel straight lines (by condition) АС and ВМ secant СМ. Then the triangles AOС and BOM are similar by the first sign of similarity of triangles, at two angles.
Then AC / BM = CO / CM.
15/3 = 10 / CM.
CM = 3 * 10/15 = 2 cm.
Answer: The length of the segment CM = 2 cm.



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