Segments AB and KP intersect at point O so that OA = OB, OK = OP. Prove that triangle AOP = triangle BOK

In triangles AOP and BOK, the angle AOP = BOK as vertical angles at the intersection of straight lines AB and KP.

By condition, AO = OB, OK = OP, then triangle AOB is equal to triangle BOK by the first sign of equality of triangles, along two sides and the angle between them, which was required to be proved.



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