Side ab of triangle abc is 17 cm. Side ac is twice as large as side ab and side bc is 10 cm less than side ac. Find the perimeter of triangle abc.

Given:
triangle ABC,
AB = 17 centimeters,
AC = 2 * AB,
AC – 10 = BC,
Find the perimeter of the triangle ABC, that is, P ABC -?
Decision:
Consider a triangle ABC.
1. The length of the AC side = 2 * AB = 2 * 17 = 34 (centimeters);
2. Side length BC = AC – 10 = 34 – 10 = 24 (centimeters).
3. The perimeter of the triangle ABC is the sum of the lengths of its sides, that is, P ABC = AB + BC + AC = 17 + 24 + 34 = 41 + 24 = 65 (centimeters).
Answer: 65 centimeters.