Side AB of triangle ABC is 17 cm, side AC is twice as large as side AB, and side BC is 10 cm

univerkov | March 9, 2021 | education

Side AB of triangle ABC is 17 cm, side AC is twice as large as side AB, and side BC is 10 cm less than side AC. Find the perimeter of the ABC triangle.

Since the side of the triangle AB = 17 cm, and the side of the AC is twice the side of AB, we have: AC = 2 * AB, AC = 2 * 17 = 34 cm.The side of the triangle BC is 10 cm less than the AC side, therefore BC = AC -10, BC = 34-10 = 24 cm. The perimeter of a triangle is equal to the sum of the lengths of its sides: P = AB + AC + BC, P = 17 + 34 + 24 = 75 cm.
Answer: The perimeter of triangle ABC is 75 cm.

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