Side AB of triangle ABC is 3/20 cm. Side BC is 5 times larger than side AB, and side

Side AB of triangle ABC is 3/20 cm. Side BC is 5 times larger than side AB, and side AC is 11/15 cm larger than side AB. Find the perimeter of triangle ABC.

1 Find the side of the triangle BC if it is 5 times larger than the side AB:

BC = 3/20 * 5 = 3/4 cm;

2 Find the side of the triangle AC if it is 11/15 cm larger than the side AB:

AC = 3/20 + 11/15 = 3/20 * 60/60 + 11/15 * 60/60 = (9 + 44) / 60 = 53/60 cm;

3 Find the perimeter of triangle ABC:

P = (AB + BC + AC) = 3/20 + 3/4 +53/60 = 3/20 * 60/60 + 3/4 * 60/60 + 53/60 =

= (9 + 45 + 53) / 60 = 107/60 = 1 47/60 cm;

Answer: The perimeter of triangle ABC is 1 47/60 cm.