# Sleds with children begin to roll down the mountain and, evenly accelerating, in 9 seconds they pass 15 m

**Sleds with children begin to roll down the mountain and, evenly accelerating, in 9 seconds they pass 15 m. The weight of sleds with children is 73 kg. What is the acceleration of the sled equal? a = ms2 (result rounded to tenths). What is the resulting force on the sled? Fres = H (the result was rounded to tenths).**

V0 = 0 m / s.

t = 9 s.

S = 15 m.

m = 73 kg.

a -?

Fr -?

Since the sleds from the mountain move with a constant acceleration a and from a state of rest V0, their path S will be determined by the formula: S = a * t ^ 2/2, where t is the time of movement.

We express the acceleration of the sleigh by the formula: a = 2 * S / t ^ 2.

a = 2 * 15 m / (9 s) ^ 2 = 0.37 m / s2.

According to 2 Newton’s law, the resultant of all forces Fr that act on the sled is equal to the product of the mass of the sled with children m by their acceleration a: Fr = m * a.

Fr = 73 kg * 0.37 m / s2 = 27 N.

Answer: the sled with children moves with an acceleration of a = 0.37 m / s2, the resultant of all the forces that act on the sled is Fr = 27 N.