Sleds with children begin to roll down the mountain and, evenly accelerating, in 9 seconds they pass 15 m. The weight of sleds with children is 73 kg. What is the acceleration of the sled equal? a = ms2 (result rounded to tenths). What is the resulting force on the sled? Fres = H (the result was rounded to tenths).
V0 = 0 m / s.
t = 9 s.
S = 15 m.
m = 73 kg.
Since the sleds from the mountain move with a constant acceleration a and from a state of rest V0, their path S will be determined by the formula: S = a * t ^ 2/2, where t is the time of movement.
We express the acceleration of the sleigh by the formula: a = 2 * S / t ^ 2.
a = 2 * 15 m / (9 s) ^ 2 = 0.37 m / s2.
According to 2 Newton’s law, the resultant of all forces Fr that act on the sled is equal to the product of the mass of the sled with children m by their acceleration a: Fr = m * a.
Fr = 73 kg * 0.37 m / s2 = 27 N.
Answer: the sled with children moves with an acceleration of a = 0.37 m / s2, the resultant of all the forces that act on the sled is Fr = 27 N.
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