Sodium hydroxide reacts with hydrochloric acid. Determine the mass of the salt if 18.9 g of hydrochloric acid was used for the reaction.

Given:
m (HCl) = 18.9 g
To find:
m (NaCl)
Decision:
NaOH + HCl = NaCl + H2O
n (HCl) = 18.9 / 36.5 = 0.517 mol
n (HCl): n (NaCl) = 1: 1
n (NaCl) = 0.517 mol
m (NaCl) = 0.517 * 58.5 = 30.24 g
Answer: 30.24 g



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