Sodium hydroxide solution was added to 100 g of copper (II) sulfate solution. Determine the mass

Sodium hydroxide solution was added to 100 g of copper (II) sulfate solution. Determine the mass of sodium hydroxide that has reacted.

Given:
m (CuSO4) = 100 g
To find:
m (NaOH) =?
Decision:
1) Let’s compose the equation of the chemical reaction, let the mass of sodium hydroxide be x g.
СuSO4 + 2NaOH = Na2SO4 + Cu (OH) 2
2) Find the molecular weights of the substances we need.
M (CuSO4) = 64 + 32 + 64 = 160 g / mol
M (NaOH) = 23 + 16 + 1 = 40 g / mol, since 2 mol is 80 g / mol.
2) Find the mass of sodium hydroxide.
100 g: 160 g / mol = x g: 80 g / mol
x = (100 x 80): 160 = 50 g
Answer: m (NaOH) = 50 g.