Sodium hydroxide was added to 20 grams of a solution containing 5% copper sulfate.

Sodium hydroxide was added to 20 grams of a solution containing 5% copper sulfate. Calculate the mass of the precipitate formed.

Reaction equation:
CuSO4 + 2NaOH = Na2SO4 + Cu (OH) 2.
Copper hydroxide precipitates.
Find the mass of copper sulfate in the original solution:
m (CuSO4) = mr-pa • W / 100% = 20 • 5/100 = 1 g.
Knowing the molar masses of substances, we will compose the expression:
Mr (CuSO4) = 160 g / mol.
Mr (Cu (OH) 2) = 98 g / mol.
From 160 g of copper sulfate, 98 g of copper hydroxide precipitate is formed,
and from 1 g – x g.
We find the mass of the sediment:
m (Cu (OH) 2) = 1 * 98/160 = 0.6 g.



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