Sodium hydroxide was added to a solution containing 32 g of copper sulfate.

Sodium hydroxide was added to a solution containing 32 g of copper sulfate. Calculate the mass and amount of the sediment formed.

Given:
m (CuSO4) = 32 g

To find:
m (draft) -?
n (sediment) -?

1) CuSO4 + 2NaOH => Cu (OH) 2 ↓ + Na2SO4;
2) n (CuSO4) = m / M = 32/160 = 0.2 mol;
3) n (Cu (OH) 2) = n (CuSO4) = 0.2 mol;
4) m (Cu (OH) 2) = n * M = 0.2 * 98 = 19.6 g.

Answer: The mass of Cu (OH) 2 is 19.6 g; the amount of substance is 0.2 mol.