Sodium oxide weighing 24.8 g reacted with 18.25 g of hydrochloric acid. Determine the mass of the formed salt.

Given:
m (Na2O) = 24.8 g
m (HCl) = 18.25 g

To find:
m (salt) -?

1) Na2O + 2HCl => 2NaCl + H2O;
2) n (Na2O) = m / M = 24.8 / 62 = 0.4 mol;
3) n (HCl) = m / M = 18.25 / 36.5 = 0.5 mol;
4) n (NaCl) = n (HCl) = 0.5 mol;
5) m (NaCl) = n * M = 0.5 * 58.5 = 29.25 g.

Answer: The mass of NaCl is 29.25 g.



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