Sodium oxide weighing 6.2 g was dipped in 10% sodium hydroxide solution weighing 120 g.
| December 23, 2020 | education
Sodium oxide weighing 6.2 g was dipped in 10% sodium hydroxide solution weighing 120 g. Determine the mass fraction of sodium hydroxide in the resulting solution.
The solution to this problem:
Na2O + H2O = 2NaOH
n (Na2O) = 6.2 / 62 = 0.1 mol
n (NaOH) = 0.2 mol
m (NaOH) = 0.2 * 40 = 8 grams
m (NaOH) = 120 * 0.1 = 12 grams
m (NaOH) total = 12 + 8 = 20 grams
m (solution) = 120 + 6.2 = 126.2 grams
w = 20 / 126.2 * 100% = 15.85%
Answer: 126.2g
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