Sodium sulfate was added to an 8% barium chloride solution weighing 130 g. find the mass of the sediment?

Reaction equation: BaCl2 + Na2SO4 = BaSO4 + 2NaCl. The precipitate is barium sulfate. Let us find the mass of the substance of barium chloride: m in-va = w * mr-pa = 0.08 * 130 g = 10.4 g. Let us find the amount of barium chloride: n = m / M = 10.4 g / 208 g / mol = 0.05 mol. According to the reaction, from 1 mol of barium chloride, 1 mol of barium sulfate is formed, which means n (BaCl2) = n (BaSO4) = 0.05 mol. Let us find the mass of the sediment m = n * M = 0.05 mol * 233 g / mol = 11.65 g (M is the molar mass, determined by the periodic table).
Answer: the mass of the sediment is 11.65 g.