Sodium weighing 2.3 g was placed in ethanol. calculate the amount of hydrogen released

Let’s implement the solution:
1. In accordance with the condition of the problem, we compose the equation:
m = 2.3 g. X l. -?
2Na + 2C2H5OH = C2H5ONa + H2 – substitutions, hydrogen was obtained;
2. We make calculations:
M (Na) = 22.9 g / mol;
M (H2) = 2 g / mol.
3. Determine the amount of the original substance:
Y (Na) = m / M = 2.3 / 22.9 = 0.1 mol.
4. Proportion:
0.1 mol (Na) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.1 * 1/2 = 0.05 mol.
5. Determine the volume of H2:
V (H2) = 0.05 * 22.4 = 1.12 liters.
Answer: hydrogen was obtained with a volume of 1.12 liters.