Sodium weighing 340 g was combined with chlorine. How many grams of sodium chloride was formed?

Let’s write down the solution:
1. Let’s compose the reaction equation:
2Na + Cl2 = 2NaCl – redox, leads to the formation of sodium chloride;
2. Let’s make calculations: M (Na) = 22.9 g / mol; Y (Na) = m (Na) / M (Na);
Y (Na) = 340 / 22.9 = 14.8 mol;
3. Let’s make a proportion based on the data of the reaction equation:
14.8 mol (Na) – X mol (NaCl);
-2 mol -2 mol hence, X mol (NaCl) = 14.8 * 2/2 = 14.8 mol;
4. Calculate the mass of sodium chloride: m (NaCl) = Y (NaCl) * M (NaCl);
m (NaCl) = 14.8 * 58.4 = 863.3 g.
Answer: 863.3 g of NaCl was formed during the reaction.