Sodium, weighing 9.2 g, reacted with water. Calculate the mass of the sodium hydroxide formed.

Given:
m (Na) = 9.2 g

To find:
m (NaOH) -?

Decision:
1) 2Na + 2H2O => 2NaOH + H2 ↑;
2) n (Na) = m (Na) / M (Na) = 9.2 / 23 = 0.4 mol;
3) n (NaOH) = n (Na) = 0.4 mol;
4) m (NaOH) = n (NaOH) * M (NaOH) = 0.4 * 40 = 16 g.

Answer: The mass of NaOH is 16 g.



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