Solve the Na2S + HNO3 equation, determine the oxidizing agent and the reducing agent, compose the electronic balance.
| December 11, 2020 | education
Na2S + 4HNO3 = 2NaNO3 + 2NO2 + S + 2H2O
NO3 (-) + 2H (+) + 1e = NO2 + H2O – oxidant (reduction)
S (2-) – 2e = S – reducing agent (oxidation)
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