Solve the system of equations using the algebraic addition method 3y-2x = 64.

Let’s apply the addition method to solve the system of equations.

{3 * x – 2 * y = 64;

3 * x + 7 * y = -8;

We multiply the first equation by (-1), and then we get:

{3 * x * (-1) – 2 * y * (-1) = 64 * (-1);

3 * x + 7 * y = -8;

{-3 * x + 2 * y = -64;

3 * x + 7 * y = -8;

Let’s add 2 equations.

{2 * y + 7 * y = -64 – 8;

3 * x + 7 * y = -8;

{9 * y = -72;

3 * x + 7 * y = -8;

1) 9 * y = -72;

y = -72/9;

y = -8;

2) 3 * x + 7 * y = -8;

3 * x + 7 * (-8) = -8;

3 * x – 56 = -8;

3 * x = -8 + 56;

3 * x = 48;

x = 48/3;

x = 16;

Answer: x = 16 and y = -8.