Some metal with a mass of 400 g, taken at the melting point, was transferred to an amount of heat of 156 kJ.

Some metal with a mass of 400 g, taken at the melting point, was transferred to an amount of heat of 156 kJ. What is this metal if it is completely melted?

The amount of energy required to melt the metal is calculated by the formula:
Q = λ * m, where Q is the amount of heat for melting the metal (Q = 156 kJ = 156 * 10³ J), λ is the specific heat of melting of the metal (J / kg), m is the mass of the metal (m = 400 g = 0, 4 kg).
Let’s calculate the specific heat of fusion of the metal:
λ = Q / m = 156 * 10³ / 0.4 = 390 * 10³ J / kg.
Specific heat of fusion equal to 390 * 10³ J / kg corresponds to aluminum.
Answer: The metal you are looking for is aluminum.