Sound propagates in the first environment at a speed of 4500m / s, and in the second – 5000m / s

Sound propagates in the first environment at a speed of 4500m / s, and in the second – 5000m / s. the propagation time of sound in the first medium is times longer than in the second. What is the relationship between the distances that sound has traveled in these environments?

By the condition of the problem, t1 = 2 * t2, where t1 is the propagation time in the 1st medium, t2 is in the 2nd.
Then the first distance S1 = t1 * v1 = 2 * t2 * 4500 = 9000 * t2 m.,
second distance S2 = t2 * v2 = 5000 * t2.
From here we get the ratio of these distances:
S1 / S2 = 9000 * t2 / 5000 * t2 = 9000/5000 = 1.8.



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