Specific heat of fusion = 335 kJ / kg mass = 0.5 g find the amount of heat Q-?

Initial data: m (body weight) = 0.5 g.

Reference data: according to condition C (specific heat of fusion) = 335 kJ / kg = 335 * 10 ^ 3 J / kg (corresponds to the specific heat of melting of ice).

SI system: m = 0.5 g = 0.5 * 10 ^ -3 kg.

The amount of heat that must be spent on melting the body is calculated by the formula: Q = λ * m.

Let’s perform the calculation: Q = 335 * 10 ^ 3 * 0.5 * 10 ^ -3 = 167.5 J.

Answer: 167.5 Joules of thermal energy will be required.