Specify the formula of nitrogen oxide if the mass fraction of nitrogen is 36.84% oxygen 63.16%

Given:
NxOy
ω (N) = 36.84%
ω (O) = 63.16%

Find:
NxOy -?

Solution:
1) Let m (NxOy) = 100 g;
2) m (N) = ω (N) * m (NxOy) / 100% = 36.84% * 100/100% = 36.84 g;
3) n (N) = m (N) / M (N) = 36.84 / 14 = 2.631 mol;
4) m (O) = ω (O) * m (NxOy) / 100% = 63.16% * 100/100% = 63.16 g;
5) n (O) = m (O) / M (O) = 63.16 / 16 = 3.948 mol;
6) x: y = n (N): n (O) = 2.631: 3.948 = 1: 1.5 = 2: 3;
Unknown substance – N2O3 – nitric oxide (III).

Answer: Unknown substance – N2O3 – nitric oxide (III).