Specify the interval to which the root of the equation belongs log27 (3 + x) = 0

log 27 (3 + x) = 0;
3 + x = 27 ^ 0;
3 + x = 1;
We transfer the known values to one side, and the unknown ones to the other side. When transferring values, their signs are changed to the opposite sign. That is, we get:
x = 1 – 3;
x = – 2;
x = – 2 belongs to (- 3; – 1).



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