Springs with stiffness of 100 N / m and 300 N / m were connected: a) in parallel;

Springs with stiffness of 100 N / m and 300 N / m were connected: a) in parallel; b) consistently. With a spring of what rigidity can such a spring system be replaced?

Given:

k1 = 100 Newton / meter is the stiffness coefficient of the first spring;

k2 = 300 Newton / meter is the stiffness coefficient of the second spring.

It is required to determine the stiffness of the spring k (N / m), which could be replaced by 2 springs in parallel and series connection.

Parallel connection:

k = k1 + k2 = 100 + 300 = 400 Newton / meter.

With a serial connection:

1 / k = 1 / k1 + 1 / k2;

1 / k = (k1 + k2) / (k1 * k2);

k = k1 * k2 / (k1 + k2) = 100 * 300 / (100 + 300) =

= 30000/400 = 75 Newtons / meter.

Answer: with parallel connection – 400 N / m, with serial connection – 75 N / m.