Steam at 373K is introduced into a vessel containing water weighing 1 kg at a temperature of 293 K.

Steam at 373K is introduced into a vessel containing water weighing 1 kg at a temperature of 293 K. which turns into water. Steam weight 0.2 kg. determine the final water temperature

Let’s move on to the Celsius temperature scale:
t1 = 293 ° K = 20 ° C,
t2 = 373 ° K = 100 ° C,
L = 2.3 * 10 ^ 6 J / kg – specific heat of vaporization for water,
c = 4200J / (kg * ° С) – specific heat capacity of water,
m1 = 1kg,
m2 = 0.2kg.
Find t3.
To bring 1 kg of water from 20 ° C to a boiling point of 100 ° C, you need the amount of heat:
Q = m1 * c * (t2 – t1) = 1 * 4200 * 80 = 336000J;
The amount of steam required for this:
m = Q / L = 336000 / (2.3 * 10 ^ 6) = 0.146kg.
The temperature of the water in the vessel will reach the boiling point and there will be another 54 g of steam.