Steel and copper weights are balanced on the scales. Will the balance of the weights be imbalanced

Steel and copper weights are balanced on the scales. Will the balance of the weights be imbalanced if the weights are lowered into the water? The density of steel is 7800 kg \ m3, the density of copper is 8900 kg \ m3

Data: m1 (weight of steel weight) = m2 (weight of copper weight) = m.

Constants: by condition ρс (steel density) = 7800 kg / m3; ρm (copper density) = 8900 kg / m3.

The balance will be disturbed, as the loads will have different volumes, which will affect the magnitude of the buoyancy force.

Proof: Fт1 + Fа = Fт2 – Fa2.

m1 * g – ρw * g * V1 = m2 * g – ρw * g * V2 | – m * g.

ρw * g * V1 = ρw * g * V2 | : ρw * g.

V1 = V2.

m1 / ρс = m2 / ρм | : m.

1 / ρs = 1 / ρm.

1/7800 = 1/8900 (wrong, the balance will be disturbed).