Steel wire can withstand a load weighing no more than 600 kg. What is the maximum load that can be lifted

Steel wire can withstand a load weighing no more than 600 kg. What is the maximum load that can be lifted with an acceleration of 2 m / s2 so that the wire does not break?

mmax = 600 kg.

a = 2 m / s2.

g = 10 m / s2.

m -?

The maximum tensile force Nmax of the steel wire is Nmax = mmax * g.

Nmax = 600 kg * 10 m / s2 = 6000 N.

Let’s find what mass the steel wire can withstand when lifting a load with acceleration a up.

m * a = N – m * g.

N = m * a + m * g = m * (a + g).

m = N / (a + g).

m = 6000 N / (2 m / s2 + 10 m / s2) = 500 kg.

Answer: the maximum load that can be lifted with acceleration upwards is m = 500 kg.