Substances are given: oxygen, barium oxide, sulfuric acid, potassium hydroxide, sulfur oxide (4).

Substances are given: oxygen, barium oxide, sulfuric acid, potassium hydroxide, sulfur oxide (4). Which of these substances will interact with potassium? Write the equation of the corresponding reactions.

4K + O2 = 2K2O potassium is an active metal, so it reacts with oxygen to form its oxide.
BaO + 2K = K2O + Ba – since potassium is in front of barium in the row of metal activities, it displaces barium from its compound.
H2SO4 + K = K2SO4 + H2 – potassium reacts with sulfuric acid to form its salt, hydrogen is released during the reaction.
SO2 + 2K = 2K2O + S – potassium displaces sulfur from the compound, forming potassium oxide and sulfur.



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