Substances weighing 30 grams were evaporated, spending 12 kJ of energy. Find the specific heat of vaporization.
| November 27, 2020 | education
Given:
Q = 12 kJ = 12000 J
m = 30 gr = 0.03 kg
Find: L -? J / kg
Decision :
Q = L * m – the amount of heat released as a result of vaporization.
L = Q / m.
[L] = J / kg.
L = 12000 / 0.03 = 1200000/3 = 400000 (J / kg).
Answer: 400,000 J / kg.
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